What is the integral from 0 to 1 of ln(x+2) ?

The integral from 0 to 1 of ln(x+2) is 3ln(3)-1-2ln(2)

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integral from 0 to 1 of ln(x+2)

\int_{0}^{1} ln (x + 2) d x

3 ln (3) - 1 - 2 ln (2)

Decimal Notation

0.90954 \dots

Solution steps

\int_{0}^{1} ln (x + 2) d x

Apply u-substitution

: \int_{2}^{3} ln (u) d u

= \int_{2}^{3} ln (u) d u

Apply Integration By Parts

: [u ln (u) - \int 1 d u]_{2}^{3}

= [u ln (u) - \int 1 d u]_{2}^{3}

\int 1 d u = u

= [u ln (u) - u]_{2}^{3}

Compute the boundaries:

3 ln (3) - 1 - 2 ln (2)

= 3 ln (3) - 1 - 2 ln (2)

\int_{2}^{4} \frac{2 x ^{2}}{x + 2} d x

\int_{7}^{13} 4 x^{5} d x

\int_{- 1}^{9} 0.048 x^{3} - 2 x d x

\int_{1}^{5} \frac{5 ^{l n (x)}}{x} d x

\int_{2}^{4} 4 x - x^{2} d x

What is the integral from 0 to 1 of ln(x+2) ?
The integral from 0 to 1 of ln(x+2) is 3ln(3)-1-2ln(2)