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Popular >

y^'=5y^2+xy^2,y(0)=1

Solution

y^{^{'}} = 5 y^{2} + x y^{2}, y (0) = 1

Solution

y = - \frac{2}{10 x + x ^{2} - 2}

Solution steps

y^{'} (x) = 5 y^{2} + x y^{2}

Solve separable ODE:

y = - \frac{2}{10 x + x ^{2} - 2}

y = - \frac{2}{10 x + x ^{2} - 2}

Popular Examples

derivative of (-8x-2/(9x-4))

\frac{d}{d x} (\frac{- 8 x - 2}{9 x - 4})

integral of (cos(2x))^4

\int (cos (2 x))^{4} d x

implicit (dy)/(dx),y^3=x^5 implicit derivative

\frac{d y}{d x}, y^{3} = x^{5}

inverse oflaplace e^{ax}inverse laplace

e^{a x}

derivative of f(x)=(e^x)/(x^2-1)

\frac{d}{d x} f (x) = \frac{e ^{x}}{x ^{2} - 1}

Frequently Asked Questions (FAQ)

What is the solution for y^'=5y^2+xy^2,y(0)=1 ?
The solution for y^'=5y^2+xy^2,y(0)=1 is y=-2/(10x+x^2-2)