What is the integral from 0 to 1 of 1/(x^{1/5)} ?

The integral from 0 to 1 of 1/(x^{1/5)} is 5/4

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integral from 0 to 1 of 1/(x^{1/5)}

\int_{0}^{1} \frac{1}{x ^{\frac{1}{5}}} d x

\frac{5}{4}

Decimal Notation

1.25

Solution steps

\int_{0}^{1} \frac{1}{x ^{\frac{1}{5}}} d x

Apply the Power Rule

: [\frac{5}{4} x^{\frac{4}{5}}]_{0}^{1}

= [\frac{5}{4} x^{\frac{4}{5}}]_{0}^{1}

Compute the boundaries:

\frac{5}{4}

= \frac{5}{4}

\int_{1}^{2} x^{2} \cdot \frac{3}{7} x^{2} d x

\int_{- 2 x}^{3 x^{2}} cos (t) d t

\int_{0}^{1} ln x^{2} + 1 d x

\int_{1}^{z} y e^{y^{2} - z} d y

\int_{0}^{1} (3 x^{2} + 2 x) d x

What is the integral from 0 to 1 of 1/(x^{1/5)} ?
The integral from 0 to 1 of 1/(x^{1/5)} is 5/4