What is the tangent of f(x)=x+9/x ,(9,10) ?

The tangent of f(x)=x+9/x ,(9,10) is y= 8/9 x+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x+9/x ,(9,10)

tangent of

f (x) = x + \frac{9}{x}, (9, 10)

y = \frac{8}{9} x + 2

Solution steps

Find the slope of

f (x) = x + \frac{9}{x} : \frac{df ( x )}{d x} = 1 - \frac{9}{x ^{2}}

Compute the slope of

f (x) = x + \frac{9}{x}

(9, 10) : m = \frac{8}{9}

Find the line with slope m=

\frac{8}{9}

and passing through

(9, 10) : y = \frac{8}{9} x + 2

y = \frac{8}{9} x + 2

\int cos^{3} (t) - sin^{2} (t) cos (t) d t

y = x^{2} - 5 x - 6

f (x) = \frac{( x + 9 )}{x ^{2} - 7 x + 1}

g (x) = \frac{7}{x}

\frac{s}{( s + 1 ) ^{2}}

What is the tangent of f(x)=x+9/x ,(9,10) ?
The tangent of f(x)=x+9/x ,(9,10) is y= 8/9 x+2