What is the derivative of g(x)= 7/(sqrt(x)) ?

The derivative of g(x)= 7/(sqrt(x)) is -7/(2x^{3/2)}

What is the first derivative of g(x)= 7/(sqrt(x)) ?

The first derivative of g(x)= 7/(sqrt(x)) is -7/(2x^{3/2)}

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derivative of

g (x) = \frac{7}{x}

- \frac{7}{2 x ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{7}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 7 \frac{d}{d x} (x^{- \frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 7 (- \frac{1}{2} x^{- \frac{1}{2} - 1})

Simplify

7 (- \frac{1}{2} x^{- \frac{1}{2} - 1}) : - \frac{7}{2 x ^{\frac{3}{2}}}

= - \frac{7}{2 x ^{\frac{3}{2}}}

\frac{s}{( s + 1 ) ^{2}}

\int \frac{4 x ^{5}}{1 - 12 x ^{6}} d x

12 x^{3} - 18 x^{2}

\frac{d y}{d x} + 2 y = k

What is the derivative of g(x)= 7/(sqrt(x)) ?
The derivative of g(x)= 7/(sqrt(x)) is -7/(2x^{3/2)}
What is the first derivative of g(x)= 7/(sqrt(x)) ?
The first derivative of g(x)= 7/(sqrt(x)) is -7/(2x^{3/2)}