What is the integral from 0 to 60 of x(1/1800 x) ?

The integral from 0 to 60 of x(1/1800 x) is 40

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integral from 0 to 60 of x(1/1800 x)

\int_{0}^{60} x (\frac{1}{1800} x) d x

40

Solution steps

\int_{0}^{60} x \frac{1}{1800} x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{1800} \cdot \int_{0}^{60} xx d x

Simplify

xx : x^{2}

= \frac{1}{1800} \cdot \int_{0}^{60} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{60}

= \frac{1}{1800} [\frac{x ^{3}}{3}]_{0}^{60}

Compute the boundaries:

72000

= \frac{1}{1800} \cdot 72000

Simplify

= 40

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What is the integral from 0 to 60 of x(1/1800 x) ?
The integral from 0 to 60 of x(1/1800 x) is 40