What is the integral from 8 to 10 of 2x^{-3} ?

The integral from 8 to 10 of 2x^{-3} is 9/1600

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integral from 8 to 10 of 2x^{-3}

\int_{8}^{10} 2 x^{- 3} d x

\frac{9}{1600}

Decimal

0.005625

Solution steps

\int_{8}^{10} 2 x^{- 3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{8}^{10} x^{- 3} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{8}^{10}

= 2 [- \frac{1}{2 x ^{2}}]_{8}^{10}

Compute the boundaries:

\frac{9}{3200}

= 2 \cdot \frac{9}{3200}

Simplify

= \frac{9}{1600}

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What is the integral from 8 to 10 of 2x^{-3} ?
The integral from 8 to 10 of 2x^{-3} is 9/1600