What is the integral from 0 to x of sqrt(4+t^6) ?

The integral from 0 to x of sqrt(4+t^6) is xsqrt(t^6+4)

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integral from 0 to x of sqrt(4+t^6)

\int_{0}^{x} 4 + t^{6} d x

x t^{6} + 4

Solution steps

\int_{0}^{x} 4 + t^{6} d x

Integral of a constant:

\int a d x = a x

= [4 + t^{6} x]_{0}^{x}

Compute the boundaries:

x t^{6} + 4

= x t^{6} + 4

\int_{0}^{1} 1 + 8 t^{2} d t

\int_{0}^{4} (2 x - 3) d x

\int_{0}^{1} π (y - y^{2})^{2} d y

\int_{x}^{2} t d t

What is the integral from 0 to x of sqrt(4+t^6) ?
The integral from 0 to x of sqrt(4+t^6) is xsqrt(t^6+4)