What is the integral from 2 to 3 of xsqrt(x^2+9) ?

The integral from 2 to 3 of xsqrt(x^2+9) is 18sqrt(2)-(13sqrt(13))/3

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integral from 2 to 3 of xsqrt(x^2+9)

\int_{2}^{3} x x^{2} + 9 d x

182 - \frac{13 13}{3}

Decimal Notation

9.83178 \dots

Solution steps

\int_{2}^{3} x x^{2} + 9 d x

Apply u-substitution

: \int_{13}^{32} u^{2} d u

= \int_{13}^{32} u^{2} d u

Apply the Power Rule

: [\frac{u ^{3}}{3}]_{13}^{32}

= [\frac{u ^{3}}{3}]_{13}^{32}

Compute the boundaries:

182 - \frac{13 13}{3}

= 182 - \frac{13 13}{3}

\int_{1}^{\infty} - ln (x) d x

\int_{3}^{3.5} 2 d x

\int_{1}^{2} (4 - r^{2}) r d r

\int_{2}^{4} (ln (x))^{3} d x

\int_{0}^{1} \frac{12}{x ^{2} - 9} d x

What is the integral from 2 to 3 of xsqrt(x^2+9) ?
The integral from 2 to 3 of xsqrt(x^2+9) is 18sqrt(2)-(13sqrt(13))/3