What is the integral from-1 to 1 of 6^x ?

The integral from-1 to 1 of 6^x is (35)/(6ln(6))

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integral from-1 to 1 of 6^x

\int_{- 1}^{1} 6^{x} d x

\frac{35}{6 ln ( 6 )}

Decimal Notation

3.25564 \dots

Solution steps

\int_{- 1}^{1} 6^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{6 ^{x}}{ln ( 6 )}]_{- 1}^{1}

Compute the boundaries:

\frac{35}{6 ln ( 6 )}

= \frac{35}{6 ln ( 6 )}

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What is the integral from-1 to 1 of 6^x ?
The integral from-1 to 1 of 6^x is (35)/(6ln(6))