What is the integral from 1 to 4 of (x^3+2x+5) ?

The integral from 1 to 4 of (x^3+2x+5) is 375/4

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integral from 1 to 4 of (x^3+2x+5)

\int_{1}^{4} (x^{3} + 2 x + 5) d x

\frac{375}{4}

Decimal Notation

93.75

Solution steps

\int_{1}^{4} x^{3} + 2 x + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x^{3} d x + \int_{1}^{4} 2 x d x + \int_{1}^{4} 5 d x

\int_{1}^{4} x^{3} d x = \frac{255}{4}

\int_{1}^{4} 2 x d x = 15

\int_{1}^{4} 5 d x = 15

= \frac{255}{4} + 15 + 15

Simplify

\frac{255}{4} + 15 + 15 : \frac{375}{4}

= \frac{375}{4}

\int_{- 2}^{1} (2 x^{2} + 2) d x

\int_{0}^{1.25} x^{3} + 2 x^{2} - 3 d x

\int_{0}^{y^{3}} e^{y^{4}} d y

\int_{0}^{\frac{π}{2}} sin^{2} (2 t) d t

What is the integral from 1 to 4 of (x^3+2x+5) ?
The integral from 1 to 4 of (x^3+2x+5) is 375/4