What is the integral from 0 to 3 of (5x^2+9x) ?

The integral from 0 to 3 of (5x^2+9x) is 171/2

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integral from 0 to 3 of (5x^2+9x)

\int_{0}^{3} (5 x^{2} + 9 x) d x

\frac{171}{2}

Decimal Notation

85.5

Solution steps

\int_{0}^{3} 5 x^{2} + 9 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} 5 x^{2} d x + \int_{0}^{3} 9 x d x

\int_{0}^{3} 5 x^{2} d x = 45

\int_{0}^{3} 9 x d x = \frac{81}{2}

= 45 + \frac{81}{2}

Simplify

45 + \frac{81}{2} : \frac{171}{2}

= \frac{171}{2}

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What is the integral from 0 to 3 of (5x^2+9x) ?
The integral from 0 to 3 of (5x^2+9x) is 171/2