What is the integral from 0 to 1 of (x+\sqrt[4]{x}) ?

The integral from 0 to 1 of (x+\sqrt[4]{x}) is 13/10

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integral from 0 to 1 of (x+\sqrt[4]{x})

\frac{13}{10}

Decimal Notation

1.3

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int_{0}^{1} x d x = \frac{1}{2}

= \frac{1}{2} + \frac{4}{5}

Simplify

\frac{1}{2} + \frac{4}{5} : \frac{13}{10}

= \frac{13}{10}

\int_{0}^{2} - 2 x^{2} 2 x - x^{2} d x

\int_{0}^{y} sin (y) d y

\int_{1}^{3} \frac{x}{x ^{4} + 1} d x

\int_{0}^{1} 2 x x^{2} + 3 d x

\int_{0}^{10} \frac{1}{20} d y

What is the integral from 0 to 1 of (x+\sqrt[4]{x}) ?
The integral from 0 to 1 of (x+\sqrt[4]{x}) is 13/10