What is the integral from 0 to y of sin(y) ?

The integral from 0 to y of sin(y) is -cos(y)+1

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integral from 0 to y of sin(y)

\int_{0}^{y} sin (y) d y

- cos (y) + 1

Solution steps

\int_{0}^{y} sin (y) d y

Use the common integral:

\int sin (y) d y = - cos (y)

= [- cos (y)]_{0}^{y}

Compute the boundaries:

- cos (y) + 1

= - cos (y) + 1

\int_{1}^{3} \frac{x}{x ^{4} + 1} d x

\int_{0}^{1} 2 x x^{2} + 3 d x

\int_{0}^{10} \frac{1}{20} d y

\int_{0}^{4} (\frac{1}{5}) e^{\frac{- x}{5}} d x

What is the integral from 0 to y of sin(y) ?
The integral from 0 to y of sin(y) is -cos(y)+1