What is the integral from 0 to 2 of \sqrt[3]{x-1} ?

The integral from 0 to 2 of \sqrt[3]{x-1} is 0

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integral from 0 to 2 of \sqrt[3]{x-1}

0

Solution steps

Apply u-substitution

Apply the Power Rule

: [\frac{3}{4} u^{\frac{4}{3}}]_{- 1}^{1}

= [\frac{3}{4} u^{\frac{4}{3}}]_{- 1}^{1}

Compute the boundaries:

0

= 0

\int_{1}^{10} x - 1 d x

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\int_{2}^{5} 5 x^{2} + 13 x - 6 d x

What is the integral from 0 to 2 of \sqrt[3]{x-1} ?
The integral from 0 to 2 of \sqrt[3]{x-1} is 0