What is the integral from pi/3 to 2pi of sin(x) ?

The integral from pi/3 to 2pi of sin(x) is -1/2

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integral from pi/3 to 2pi of sin(x)

\int_{\frac{π}{3}}^{2 π} sin (x) d x

- \frac{1}{2}

Decimal Notation

- 0.5

Solution steps

\int_{\frac{π}{3}}^{2 π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{\frac{π}{3}}^{2 π}

Compute the boundaries:

- \frac{1}{2}

= - \frac{1}{2}

\int_{- 1}^{1} (\frac{1}{x}) d x

\int_{2}^{8} \frac{x}{x + 2 x} d x

\int_{0}^{2} (\frac{x}{2} + 1) d x

\int_{0}^{\frac{π}{2}} 7 sin (t) - 2 cos (t) d t

\int_{2}^{3} \frac{x ^{3} + 2}{x ^{4}} d x

What is the integral from pi/3 to 2pi of sin(x) ?
The integral from pi/3 to 2pi of sin(x) is -1/2