What is the integral from 16 to 2y+4 of 1 ?

The integral from 16 to 2y+4 of 1 is 2y-12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 16 to 2y+4 of 1

\int_{16}^{2 y + 4} 1

2 y - 12

Solution steps

\int_{16}^{2 y + 4} 1 d y

Integral of a constant:

\int a d x = a x

= [1 \cdot y]_{16}^{2 y + 4}

Simplify

= [y]_{16}^{2 y + 4}

Compute the boundaries:

2 y - 12

= 2 y - 12

\int_{0}^{2} (x^{2} y e^{x y}) d x

\int_{2}^{4} x^{3} + 4 d x

\int_{1}^{e^{10}} x ln (x) d x

\int_{x}^{\frac{π}{2}} \frac{sin ( x )}{x} d x

\int_{1}^{2} - (x^{3} - 2 x^{2} - 5 x + 6) d x

What is the integral from 16 to 2y+4 of 1 ?
The integral from 16 to 2y+4 of 1 is 2y-12