What is the integral from x to pi/2 of (sin(x))/x ?

The integral from x to pi/2 of (sin(x))/x is \Si(pi/2)-\Si(x)

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integral from x to pi/2 of (sin(x))/x

\int_{x}^{\frac{π}{2}} \frac{sin ( x )}{x} d x

Si (\frac{π}{2}) - Si (x)

Solution steps

\int_{x}^{\frac{π}{2}} \frac{sin ( x )}{x} d x

Use the nonelementary integral:

\int \frac{sin ( x )}{x} d x = Si (x)

= [Si (x)]_{x}^{\frac{π}{2}}

Compute the boundaries:

Si (\frac{π}{2}) - Si (x)

= Si (\frac{π}{2}) - Si (x)

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\int_{- 2}^{0} x^{2} - 4 d x

\int_{- 1}^{1} 2 x e^{- inπ x} d x

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\int_{0}^{3} (3 - x^{2}) d x

What is the integral from x to pi/2 of (sin(x))/x ?
The integral from x to pi/2 of (sin(x))/x is \Si(pi/2)-\Si(x)