What is the integral from 0 to 8 of 8+\sqrt[3]{x} ?

The integral from 0 to 8 of 8+\sqrt[3]{x} is 76

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integral from 0 to 8 of 8+\sqrt[3]{x}

76

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int_{0}^{8} 8 d x = 64

= 64 + 12

Simplify

= 76

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What is the integral from 0 to 8 of 8+\sqrt[3]{x} ?
The integral from 0 to 8 of 8+\sqrt[3]{x} is 76