What is the integral from 0 to 1/2 of x/2 ?

The integral from 0 to 1/2 of x/2 is 1/16

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integral from 0 to 1/2 of x/2

\int_{0}^{\frac{1}{2}} \frac{x}{2} d x

\frac{1}{16}

Decimal Notation

0.0625

Solution steps

\int_{0}^{\frac{1}{2}} \frac{x}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{\frac{1}{2}} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{\frac{1}{2}}

= \frac{1}{2} [\frac{x ^{2}}{2}]_{0}^{\frac{1}{2}}

Compute the boundaries:

\frac{1}{8}

= \frac{1}{2} \cdot \frac{1}{8}

Simplify

= \frac{1}{16}

\int_{0}^{1} 1 + \frac{1}{x ^{2}} d x

\int_{0}^{2} sec (x) d x

\int_{0}^{1} (5 x) d x

\int_{- π}^{0} - 1

\int_{1}^{2} (- x + 2) d x

What is the integral from 0 to 1/2 of x/2 ?
The integral from 0 to 1/2 of x/2 is 1/16