What is the integral from 0 to 4 of r^2 ?

The integral from 0 to 4 of r^2 is 64/3

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integral from 0 to 4 of r^2

\int_{0}^{4} r^{2} d r

\frac{64}{3}

Decimal Notation

21.33333 \dots

Solution steps

\int_{0}^{4} r^{2} d r

Apply the Power Rule

: [\frac{r ^{3}}{3}]_{0}^{4}

= [\frac{r ^{3}}{3}]_{0}^{4}

Compute the boundaries:

\frac{64}{3}

= \frac{64}{3}

\int_{0}^{2} x^{3} - 2 x d x

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\int_{0}^{1} 7 x y x^{2} + y^{2} d y

\int_{0}^{a} \frac{x}{a ^{2} - x ^{2}} d x

What is the integral from 0 to 4 of r^2 ?
The integral from 0 to 4 of r^2 is 64/3