What is the integral from 1 to 5 of g(x) ?

The integral from 1 to 5 of g(x) is g*12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 5 of g(x)

\int_{1}^{5} g (x) d x

g \cdot 12

Solution steps

\int_{1}^{5} gx d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= g \cdot \int_{1}^{5} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{1}^{5}

= g [\frac{x ^{2}}{2}]_{1}^{5}

Compute the boundaries:

12

= g \cdot 12

\int_{1}^{5} \frac{x ^{2}}{12} d x

\int_{0}^{1} 7 x y x^{2} + y^{2} d y

\int_{0}^{a} \frac{x}{a ^{2} - x ^{2}} d x

\int_{0}^{\frac{3 π}{4}} x^{3} sin (2 x) d x

\int_{y}^{e} \frac{ln ( x )}{x} d x

What is the integral from 1 to 5 of g(x) ?
The integral from 1 to 5 of g(x) is g*12