What is the derivative of x^2-cos(2x) ?

The derivative of x^2-cos(2x) is 2x+2sin(2x)

What is the first derivative of x^2-cos(2x) ?

The first derivative of x^2-cos(2x) is 2x+2sin(2x)

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\frac{d}{d x} (x^{2} - cos (2 x))

2 x + 2 sin (2 x)

Solution steps

\frac{d}{d x} (x^{2} - cos (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (cos (2 x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

= 2 x - (- sin (2 x) \cdot 2)

Simplify

= 2 x + 2 sin (2 x)

(12 + x^{2}) y^{^{'}} - 2 x y = 0

x \to 0 + lim (x^{x})

\frac{\partial}{\partial x} (x^{6} - 8 x^{3} y)

\int λ e^{- λ t} d t

n = 0 \sum \infty (\frac{1}{3})^{n - 1}

What is the derivative of x^2-cos(2x) ?
The derivative of x^2-cos(2x) is 2x+2sin(2x)
What is the first derivative of x^2-cos(2x) ?
The first derivative of x^2-cos(2x) is 2x+2sin(2x)