What is the integral from-1 to 1 of (y^2-2-e^y) ?

The integral from-1 to 1 of (y^2-2-e^y) is -e+1/e-10/3

Popular >

integral from-1 to 1 of (y^2-2-e^y)

\int_{- 1}^{1} (y^{2} - 2 - e^{y}) d y

- e + \frac{1}{e} - \frac{10}{3}

Decimal Notation

- 5.68373 \dots

Solution steps

\int_{- 1}^{1} y^{2} - 2 - e^{y} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} y^{2} d y - \int_{- 1}^{1} 2 d y - \int_{- 1}^{1} e^{y} d y

\int_{- 1}^{1} y^{2} d y = \frac{2}{3}

\int_{- 1}^{1} 2 d y = 4

\int_{- 1}^{1} e^{y} d y = e - \frac{1}{e}

= \frac{2}{3} - 4 - (e - \frac{1}{e})

Simplify

\frac{2}{3} - 4 - (e - \frac{1}{e}) : - e + \frac{1}{e} - \frac{10}{3}

= - e + \frac{1}{e} - \frac{10}{3}

\int_{1}^{2} (x^{3} - 3 x^{2} + 2 x) d x

\int_{0}^{2} 2 t^{2} d t

\int_{1}^{3} 2 x^{2} e^{x^{3}} d x

\int_{\frac{π}{3}}^{\frac{π}{2}} ln (sin (x)) d x

\int_{3}^{5} 3 x^{2} d x

What is the integral from-1 to 1 of (y^2-2-e^y) ?
The integral from-1 to 1 of (y^2-2-e^y) is -e+1/e-10/3