What is the integral from 0 to 9pi of 3+sin(x) ?

The integral from 0 to 9pi of 3+sin(x) is 27pi+2

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integral from 0 to 9pi of 3+sin(x)

\int_{0}^{9 π} 3 + sin (x) d x

27 π + 2

Decimal Notation

86.82300 \dots

Solution steps

\int_{0}^{9 π} 3 + sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{9 π} 3 d x + \int_{0}^{9 π} sin (x) d x

\int_{0}^{9 π} 3 d x = 27 π

\int_{0}^{9 π} sin (x) d x = 2

= 27 π + 2

\int_{- π}^{π} sin (x) \cdot sin (n x) d x

\int_{- 2}^{1} x^{2} - 4 d x

\int_{0}^{1} 35 + x^{2} d x

\int_{0}^{x} e^{- 2 t^{4}} d t

\int_{3}^{\infty} \frac{8}{x ^{3}} d x

What is the integral from 0 to 9pi of 3+sin(x) ?
The integral from 0 to 9pi of 3+sin(x) is 27pi+2