What is the solution for (x^2+1)(dy)/(dx)+3xy=6x ?

The solution for (x^2+1)(dy)/(dx)+3xy=6x is y=(c_{1})/((x^2+1)^{3/2)}+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2+1)(dy)/(dx)+3xy=6x

(x^{2} + 1) \frac{d y}{d x} + 3 x y = 6 x

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 2

Solution steps

(x^{2} + 1) \frac{d y}{d x} + 3 x y = 6 x

Solve separable ODE:

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 2

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 2

x \to - \infty lim (e^{x} x^{2})

\int cos^{9} (x) sin (x) d x

\int_{1}^{2} \frac{1}{x x ^{2} - 1} d x

\frac{\partial}{\partial x} (\frac{( x - y )}{x ^{2} + y ^{2}})

\frac{\partial}{\partial y} (x y e^{6 y})

What is the solution for (x^2+1)(dy)/(dx)+3xy=6x ?
The solution for (x^2+1)(dy)/(dx)+3xy=6x is y=(c_{1})/((x^2+1)^{3/2)}+2