What is the integral from 0 to 1 of-2t ?

The integral from 0 to 1 of-2t is -1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of-2t

\int_{0}^{1} - 2 t d t

- 1

Solution steps

\int_{0}^{1} - 2 t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int_{0}^{1} t d t

Apply the Power Rule

: [\frac{t ^{2}}{2}]_{0}^{1}

= - 2 [\frac{t ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= - 2 \cdot \frac{1}{2}

Simplify

= - 1

\int_{0}^{0.4} x d x

\int_{0}^{1} ln (x + 10) d x

\int_{t}^{2} - x ln (x - 1) d x

\int_{1}^{4} 4 t^{2} d t

\int_{2}^{0} 2 x d x