What is the integral from 0 to 1 of ln(x+10) ?

The integral from 0 to 1 of ln(x+10) is 11ln(11)-1-10ln(10)

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integral from 0 to 1 of ln(x+10)

\int_{0}^{1} ln (x + 10) d x

11 ln (11) - 1 - 10 ln (10)

Decimal Notation

2.35099 \dots

Solution steps

\int_{0}^{1} ln (x + 10) d x

Apply u-substitution

: \int_{10}^{11} ln (u) d u

= \int_{10}^{11} ln (u) d u

Apply Integration By Parts

: [u ln (u) - \int 1 d u]_{10}^{11}

= [u ln (u) - \int 1 d u]_{10}^{11}

\int 1 d u = u

= [u ln (u) - u]_{10}^{11}

Compute the boundaries:

11 ln (11) - 1 - 10 ln (10)

= 11 ln (11) - 1 - 10 ln (10)

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What is the integral from 0 to 1 of ln(x+10) ?
The integral from 0 to 1 of ln(x+10) is 11ln(11)-1-10ln(10)