What is the integral from 0 to sqrt(x^2+y^2 of)1 ?

The integral from 0 to sqrt(x^2+y^2 of)1 is sqrt(x^2+y^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to sqrt(x^2+y^2 of)1

\int_{0}^{x^{2} + y^{2}} 1 d z

x^{2} + y^{2}

Solution steps

\int_{0}^{x^{2} + y^{2}} 1 d z

Integral of a constant:

\int a d x = a x

= [1 \cdot z]_{0}^{x^{2} + y^{2}}

Simplify

= [z]_{0}^{x^{2} + y^{2}}

Compute the boundaries:

x^{2} + y^{2}

= x^{2} + y^{2}

\int_{4}^{5} 3 x x^{2} - 16 d x

\int_{2}^{3} \frac{7}{1 + x ^{2}} d x

\int_{- 5}^{0} (3 + ∣ x + 4 ∣) d x

\int_{- 1}^{3} 1 + (2 y + 1)^{2} d y

\int_{0}^{9 π} x (3 + sin (x)) d x

What is the integral from 0 to sqrt(x^2+y^2 of)1 ?
The integral from 0 to sqrt(x^2+y^2 of)1 is sqrt(x^2+y^2)