What is the integral from 0 to infinity of 3e^{-7x} ?

The integral from 0 to infinity of 3e^{-7x} is 3/7

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integral from 0 to infinity of 3e^{-7x}

\int_{0}^{\infty} 3 e^{- 7 x} d x

\frac{3}{7}

Decimal Notation

0.42857 \dots

Solution steps

\int_{0}^{\infty} 3 e^{- 7 x} d x

Compute the indefinite integral:

\int 3 e^{- 7 x} d x = - \frac{3}{7} e^{- 7 x} + C

Compute the boundaries:

\int_{0}^{\infty} 3 e^{- 7 x} d x = 0 - (- \frac{3}{7})

= 0 - (- \frac{3}{7})

Simplify

= \frac{3}{7}

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What is the integral from 0 to infinity of 3e^{-7x} ?
The integral from 0 to infinity of 3e^{-7x} is 3/7