What is implicit (dy)/(dx),x^2-y^3=6 ?

The answer to implicit (dy)/(dx),x^2-y^3=6 is (dy)/(dx)=(2x)/(3y^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

implicit (dy)/(dx),x^2-y^3=6

implicit derivative

\frac{d y}{d x}, x^{2} - y^{3} = 6

\frac{d y}{d x} = \frac{2 x}{3 y ^{2}}

Solution steps

x^{2} - y^{3} = 6

Treat

y

y (x)

Differentiate both sides:

2 x - 3 y^{2} \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{2 x}{3 y ^{2}}

\frac{d y}{d x} = \frac{2 x}{3 y ^{2}}

\int cos (x) + \frac{1}{3} sin (x) - \frac{1}{x ^{2}} d x

\int_{0}^{2} e^{2 x} d x

\frac{d}{d x} ((2^{x + 1} - 3. 5^{x})^{3})

\frac{d ^{3}}{d x ^{3}} (1 + x^{2})

\int 5 x + sin (x) d x

What is implicit (dy)/(dx),x^2-y^3=6 ?
The answer to implicit (dy)/(dx),x^2-y^3=6 is (dy)/(dx)=(2x)/(3y^2)