What is (\partial)/(\partial x)(sin(pi(2x-y))) ?

The answer to (\partial)/(\partial x)(sin(pi(2x-y))) is cos(pi(2x-y))*2pi

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(\partial)/(\partial x)(sin(pi(2x-y)))

\frac{\partial}{\partial x} (sin (π (2 x - y)))

cos (π (2 x - y)) \cdot 2 π

Solution steps

\frac{\partial}{\partial x} (sin (π (2 x - y)))

Treat

y

as a constant

Apply the chain rule:

cos (π (2 x - y)) \frac{\partial}{\partial x} (π (2 x - y))

= cos (π (2 x - y)) \frac{\partial}{\partial x} (π (2 x - y))

\frac{\partial}{\partial x} (π (2 x - y)) = 2 π

= cos (π (2 x - y)) \cdot 2 π

\int x^{7} d x

\frac{d}{d x} (\frac{1 - cos ( x )}{1 + cos ( x )})

\int \frac{1}{( 25 - y ^{2} ) - x ^{2}} d x

sin (2 t) + 2 cos (2 t) + e^{- t} sin (2 t)

y^{^{'}} = 3 y^{2}

What is (\partial)/(\partial x)(sin(pi(2x-y))) ?
The answer to (\partial)/(\partial x)(sin(pi(2x-y))) is cos(pi(2x-y))*2pi