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Popular >

integral from 0 to 4 of |(1-x)|

Solution

\int_{0}^{4} ∣ (1 - x) ∣ d x

Solution

5

Solution steps

\int_{0}^{4} ∣ (1 - x) ∣ d x

Eliminate Absolutes

= \int_{0}^{1} 1 - x d x + \int_{1}^{4} - 1 + x d x

\int_{0}^{1} 1 - x d x = \frac{1}{2}

\int_{1}^{4} - 1 + x d x = \frac{9}{2}

= \frac{1}{2} + \frac{9}{2}

Simplify

\frac{1}{2} + \frac{9}{2} : 5

= 5

Graph

Popular Examples

integral from 0 to 2 of (4-x-y)

\int_{0}^{2} (4 - x - y) d y

integral from 0 to 1 of sin(x)ln(cos(x))

\int_{0}^{1} sin (x) ln (cos (x)) d x

integral from 0 to 1 of (u^2)/(u^2+1)

\int_{0}^{1} \frac{u ^{2}}{u ^{2} + 1} d u

integral from-6 to infinity of 1/(x+8)

\int_{- 6}^{\infty} \frac{1}{x + 8} d x

integral from 0 to 1 of x^9*e^{-x}

\int_{0}^{1} x^{9} \cdot e^{- x} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of |(1-x)| ?
The integral from 0 to 4 of |(1-x)| is 5