What is the integral from 0 to 2 of (x-3)^2 ?

The integral from 0 to 2 of (x-3)^2 is 26/3

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integral from 0 to 2 of (x-3)^2

\int_{0}^{2} (x - 3)^{2} d x

\frac{26}{3}

Decimal Notation

8.66666 \dots

Solution steps

\int_{0}^{2} (x - 3)^{2} d x

Expand

(x - 3)^{2} : x^{2} - 6 x + 9

= \int_{0}^{2} x^{2} - 6 x + 9 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x^{2} d x - \int_{0}^{2} 6 x d x + \int_{0}^{2} 9 d x

\int_{0}^{2} x^{2} d x = \frac{8}{3}

\int_{0}^{2} 6 x d x = 12

\int_{0}^{2} 9 d x = 18

= \frac{8}{3} - 12 + 18

Simplify

\frac{8}{3} - 12 + 18 : \frac{26}{3}

= \frac{26}{3}

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What is the integral from 0 to 2 of (x-3)^2 ?
The integral from 0 to 2 of (x-3)^2 is 26/3