What is the integral from 0 to 8 of 7+\sqrt[3]{x} ?

The integral from 0 to 8 of 7+\sqrt[3]{x} is 68

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integral from 0 to 8 of 7+\sqrt[3]{x}

\int_{0}^{8} 7 + 3 x d x

68

Solution steps

\int_{0}^{8} 7 + 3 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{8} 7 d x + \int_{0}^{8} 3 x d x

\int_{0}^{8} 7 d x = 56

\int_{0}^{8} 3 x d x = 12

= 56 + 12

Simplify

= 68

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What is the integral from 0 to 8 of 7+\sqrt[3]{x} ?
The integral from 0 to 8 of 7+\sqrt[3]{x} is 68