What is the integral from 5 to 10 of (2.6)/t ?

The integral from 5 to 10 of (2.6)/t is 2.6ln(2)

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integral from 5 to 10 of (2.6)/t

\int_{5}^{10} \frac{2.6}{t} d t

2.6 ln (2)

Decimal Notation

1.80218 \dots

Solution steps

\int_{5}^{10} \frac{2.6}{t} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2.6 \cdot \int_{5}^{10} \frac{1}{t} d t

Use the common integral:

\int \frac{1}{t} d t = ln (∣ t ∣)

= 2.6 [ln ∣ t ∣]_{5}^{10}

Compute the boundaries:

ln (10) - ln (5)

= 2.6 (ln (10) - ln (5))

Simplify

= 2.6 ln (2)

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What is the integral from 5 to 10 of (2.6)/t ?
The integral from 5 to 10 of (2.6)/t is 2.6ln(2)