What is the d/(d{x)}(({x}^2+{y}^2+{z}^2)^{-1/2}) ?

The d/(d{x)}(({x}^2+{y}^2+{z}^2)^{-1/2}) is -({x})/(({x)^2+{y}^2+{z}^2)^{3/2}}

What is the first d/(d{x)}(({x}^2+{y}^2+{z}^2)^{-1/2}) ?

The first d/(d{x)}(({x}^2+{y}^2+{z}^2)^{-1/2}) is -({x})/(({x)^2+{y}^2+{z}^2)^{3/2}}

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\frac{d}{d x} ((x^{2} + y^{2} + z^{2})^{- \frac{1}{2}})

- \frac{x}{( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} ((x^{2} + y^{2} + z^{2})^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}} \frac{d}{d x} (x^{2} + y^{2} + z^{2})

= - \frac{1}{2 ( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}} \frac{d}{d x} (x^{2} + y^{2} + z^{2})

\frac{d}{d x} (x^{2} + y^{2} + z^{2}) = 2 x

= - \frac{1}{2 ( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}} \cdot 2 x

Simplify

- \frac{1}{2 ( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}} \cdot 2 x : - \frac{x}{( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}}

= - \frac{x}{( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}}

\int \frac{1}{( x ^{2} - 100 ) ^{2}} d x

\int \frac{3 ^{- x}}{x} d x

y (x + 1) + y^{^{'}} = 0, y (- 2) = 1

\frac{\partial}{\partial y} (2 x^{3} y)

\frac{d}{d x} (x^{2} y + 4 y)

What is the d/(d{x)}(({x}^2+{y}^2+{z}^2)^{-1/2}) ?
The d/(d{x)}(({x}^2+{y}^2+{z}^2)^{-1/2}) is -({x})/(({x)^2+{y}^2+{z}^2)^{3/2}}
What is the first d/(d{x)}(({x}^2+{y}^2+{z}^2)^{-1/2}) ?
The first d/(d{x)}(({x}^2+{y}^2+{z}^2)^{-1/2}) is -({x})/(({x)^2+{y}^2+{z}^2)^{3/2}}