What is the derivative of x^2y+4y ?

The derivative of x^2y+4y is 2xy+(dy)/(dx)x^2+4(dy)/(dx)

What is the first derivative of x^2y+4y ?

The first derivative of x^2y+4y is 2xy+(dy)/(dx)x^2+4(dy)/(dx)

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\frac{d}{d x} (x^{2} y + 4 y)

2 x y + \frac{d y}{d x} x^{2} + 4 \frac{d y}{d x}

Solution steps

\frac{d}{d x} (x^{2} y + 4 y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2} y) + \frac{d}{d x} (4 y)

\frac{d}{d x} (x^{2} y) = 2 x y + \frac{d y}{d x} x^{2}

\frac{d}{d x} (4 y) = 4 \frac{d y}{d x}

= 2 x y + \frac{d y}{d x} x^{2} + 4 \frac{d y}{d x}

x = 0, y = 0, y = \frac{- x ^{2} + 8}{9}

θ \to 0 lim (\frac{θ}{sin ( θ )})

\frac{d y}{d x} + \frac{y}{x} = x^{2} y^{2}

\int \frac{4 x - 7}{2 x ^{4}} d x

\frac{\partial}{\partial x} ((x - y) (1 - x y))

What is the derivative of x^2y+4y ?
The derivative of x^2y+4y is 2xy+(dy)/(dx)x^2+4(dy)/(dx)
What is the first derivative of x^2y+4y ?
The first derivative of x^2y+4y is 2xy+(dy)/(dx)x^2+4(dy)/(dx)