What is the integral from 1 to 3 of 1/32 (3x^2+1) ?

The integral from 1 to 3 of 1/32 (3x^2+1) is 7/8

Popular >

integral from 1 to 3 of 1/32 (3x^2+1)

\int_{1}^{3} \frac{1}{32} (3 x^{2} + 1) d x

\frac{7}{8}

Decimal Notation

0.875

Solution steps

\int_{1}^{3} \frac{1}{32} (3 x^{2} + 1) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{32} \cdot \int_{1}^{3} 3 x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{32} (\int_{1}^{3} 3 x^{2} d x + \int_{1}^{3} 1 d x)

\int_{1}^{3} 3 x^{2} d x = 26

\int_{1}^{3} 1 d x = 2

= \frac{1}{32} (26 + 2)

Simplify

\frac{1}{32} (26 + 2) : \frac{7}{8}

= \frac{7}{8}

\int_{- 1}^{2} (y^{2} + 2) d y

\int_{1}^{\infty} \frac{1}{x + 6} d x

\int_{11}^{2005} x^{4} - 2 cos (x) d x

\int_{1}^{e} \frac{I n x}{x} d x

\int_{3}^{5} 8 + x^{2} d x

What is the integral from 1 to 3 of 1/32 (3x^2+1) ?
The integral from 1 to 3 of 1/32 (3x^2+1) is 7/8