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Popular >

integral from 1 to 2 of x^2+4

Solution

\int_{1}^{2} x^{2} + 4 d x

Solution

\frac{19}{3}

+1

Decimal Notation

6.33333 \dots

Solution steps

\int_{1}^{2} x^{2} + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{2} d x + \int_{1}^{2} 4 d x

\int_{1}^{2} x^{2} d x = \frac{7}{3}

\int_{1}^{2} 4 d x = 4

= \frac{7}{3} + 4

Simplify

\frac{7}{3} + 4 : \frac{19}{3}

= \frac{19}{3}

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\int_{3}^{4} \frac{1}{2 - 5 t} d t

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\int_{0}^{2} (3 x + 1) e^{2 x} d x

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\int_{1}^{4} (- 5 - x^{2}) d x

integral from 0 to sqrt(x of)1

\int_{0}^{x} 1 d y

integral from-1 to 2 of (4/3 x^3+4x^2+x)

\int_{- 1}^{2} (\frac{4}{3} x^{3} + 4 x^{2} + x) d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of x^2+4 ?
The integral from 1 to 2 of x^2+4 is 19/3