What is the solution for (dy)/(dx)+y/x =x^2y^2 ?

The solution for (dy)/(dx)+y/x =x^2y^2 is y= 2/(x(-x^2+c_{1))}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)+y/x =x^2y^2

\frac{d y}{d x} + \frac{y}{x} = x^{2} y^{2}

y = \frac{2}{x ( - x ^{2} + c _{1} )}

Solution steps

\frac{d y}{d x} + \frac{y}{x} = x^{2} y^{2}

Solve Bernoulli ODE:

y = \frac{2}{x ( - x ^{2} + c _{1} )}

y = \frac{2}{x ( - x ^{2} + c _{1} )}

\int \frac{4 x - 7}{2 x ^{4}} d x

\frac{\partial}{\partial x} ((x - y) (1 - x y))

\int_{0}^{1} \frac{1}{x ^{2} + 1} d x

\int \frac{2}{2 - x ^{2}} d x

What is the solution for (dy)/(dx)+y/x =x^2y^2 ?
The solution for (dy)/(dx)+y/x =x^2y^2 is y= 2/(x(-x^2+c_{1))}