What is the derivative of 7\sqrt[4]{x} ?

The derivative of 7\sqrt[4]{x} is 7/(4x^{3/4)}

What is the first derivative of 7\sqrt[4]{x} ?

The first derivative of 7\sqrt[4]{x} is 7/(4x^{3/4)}

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derivative of

\frac{7}{4 x ^{\frac{3}{4}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply radical rule:

= 7 \frac{d}{d x} (x^{\frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 7 \cdot \frac{1}{4} x^{\frac{1}{4} - 1}

Simplify

7 \cdot \frac{1}{4} x^{\frac{1}{4} - 1} : \frac{7}{4 x ^{\frac{3}{4}}}

= \frac{7}{4 x ^{\frac{3}{4}}}

\int_{0}^{1} \frac{1}{x ^{2} + 1} d x

\int \frac{2}{2 - x ^{2}} d x

\int \frac{sin ( x )}{cos ^{4} ( x )} d x

\frac{5 x}{( 1 + x ^{2} )}

2 x^{3} + 3 x^{2} - 12 x + 4

What is the derivative of 7\sqrt[4]{x} ?
The derivative of 7\sqrt[4]{x} is 7/(4x^{3/4)}
What is the first derivative of 7\sqrt[4]{x} ?
The first derivative of 7\sqrt[4]{x} is 7/(4x^{3/4)}