What is the integral from 0 to 6 of 0-(x^2-6x) ?

The integral from 0 to 6 of 0-(x^2-6x) is 36

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integral from 0 to 6 of 0-(x^2-6x)

\int_{0}^{6} 0 - (x^{2} - 6 x) d x

36

Solution steps

\int_{0}^{6} 0 - (x^{2} - 6 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{6} 0 d x - \int_{0}^{6} x^{2} - 6 x d x

\int_{0}^{6} 0 d x = 0

\int_{0}^{6} x^{2} - 6 x d x = - 36

= 0 - (- 36)

Simplify

= 36

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What is the integral from 0 to 6 of 0-(x^2-6x) ?
The integral from 0 to 6 of 0-(x^2-6x) is 36