What is the integral from-2 to 2 of (2x^2-8) ?

The integral from-2 to 2 of (2x^2-8) is -64/3

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integral from-2 to 2 of (2x^2-8)

\int_{- 2}^{2} (2 x^{2} - 8) d x

- \frac{64}{3}

Decimal Notation

- 21.33333 \dots

Solution steps

\int_{- 2}^{2} 2 x^{2} - 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{2} 2 x^{2} d x - \int_{- 2}^{2} 8 d x

\int_{- 2}^{2} 2 x^{2} d x = \frac{32}{3}

\int_{- 2}^{2} 8 d x = 32

= \frac{32}{3} - 32

Simplify

\frac{32}{3} - 32 : - \frac{64}{3}

= - \frac{64}{3}

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What is the integral from-2 to 2 of (2x^2-8) ?
The integral from-2 to 2 of (2x^2-8) is -64/3