en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 2 of |x^3|

Solution

\int_{- 1}^{2} x^{3} d x

Solution

\frac{17}{4}

+1

Decimal Notation

4.25

Solution steps

\int_{- 1}^{2} x^{3} d x

Eliminate Absolutes

= \int_{- 1}^{0} - x^{3} d x + \int_{0}^{2} x^{3} d x

\int_{- 1}^{0} - x^{3} d x = \frac{1}{4}

\int_{0}^{2} x^{3} d x = 4

= \frac{1}{4} + 4

Simplify

\frac{1}{4} + 4 : \frac{17}{4}

= \frac{17}{4}

Popular Examples

integral from 0 to 4 of-x+4

\int_{0}^{4} - x + 4 d x

integral from 0 to 1 of x^2e^{xy}

\int_{0}^{1} x^{2} e^{x y} d y

integral from 0 to 1 of x/(sqrt(2-x^2))

\int_{0}^{1} \frac{x}{2 - x ^{2}} d x

integral from 0 to x^3 of sin(x^2)

\int_{0}^{x^{3}} sin (x^{2}) d x

integral from 0 to 5 of xe^{-x/4}

\int_{0}^{5} x e^{- \frac{x}{4}} d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 2 of |x^3| ?
The integral from-1 to 2 of |x^3| is 17/4