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Popular >

integral from 0 to 4 of-x+4

Solution

\int_{0}^{4} - x + 4 d x

Solution

8

Solution steps

\int_{0}^{4} - x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{4} x d x + \int_{0}^{4} 4 d x

\int_{0}^{4} x d x = 8

\int_{0}^{4} 4 d x = 16

= - 8 + 16

Simplify

= 8

Popular Examples

integral from 0 to 1 of x^2e^{xy}

\int_{0}^{1} x^{2} e^{x y} d y

integral from 0 to 1 of x/(sqrt(2-x^2))

\int_{0}^{1} \frac{x}{2 - x ^{2}} d x

integral from 0 to x^3 of sin(x^2)

\int_{0}^{x^{3}} sin (x^{2}) d x

integral from 0 to 5 of xe^{-x/4}

\int_{0}^{5} x e^{- \frac{x}{4}} d x

integral from 0 to 4 of sqrt(x)+1

\int_{0}^{4} x + 1 d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of-x+4 ?
The integral from 0 to 4 of-x+4 is 8