What is the integral from 1 to 4 of sqrt(2/x) ?

The integral from 1 to 4 of sqrt(2/x) is 2sqrt(2)

Popular >

integral from 1 to 4 of sqrt(2/x)

\int_{1}^{4} \frac{2}{x} d x

22

Solution steps

\int_{1}^{4} \frac{2}{x} d x

Apply Integration By Parts

: [\frac{2}{x} x - \int - \frac{1}{2 x ^{\frac{1}{2}}} d x]_{1}^{4}

= [\frac{2}{x} x - \int - \frac{1}{2 x ^{\frac{1}{2}}} d x]_{1}^{4}

\int - \frac{1}{2 x ^{\frac{1}{2}}} d x = - 2 x

= [\frac{2}{x} x - (- 2 x)]_{1}^{4}

Simplify

= [\frac{2}{x} x + 2 x]_{1}^{4}

Compute the boundaries:

22

= 22

\int_{4}^{25 - x^{2} - y^{2}} 1 d z

\int_{0}^{1} sin (x) (1 - x) d x

\int_{0}^{2} (3 x^{2} + 9 - 9 x) d x

\int_{5}^{7} \frac{3}{( x - 6 ) ^{\frac{4}{5}}} d x

\int_{0}^{1} x^{2} + 1 x d x

What is the integral from 1 to 4 of sqrt(2/x) ?
The integral from 1 to 4 of sqrt(2/x) is 2sqrt(2)