What is the integral from-infinity to 7 of θe^θ ?

The integral from-infinity to 7 of θe^θ is 6e^7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-infinity to 7 of θe^θ

\int_{- \infty}^{7} θ e^{θ} d θ

6 e^{7}

Solution steps

\int_{- \infty}^{7} θ e^{θ} d θ

Compute the indefinite integral:

\int θ e^{θ} d θ = e^{θ} θ - e^{θ} + C

Compute the boundaries:

\int_{- \infty}^{7} θ e^{θ} d θ = 6 e^{7} - 0

= 6 e^{7} - 0

Simplify

= 6 e^{7}

\int_{0}^{\frac{1}{7}} arccos (7 x) d x

\int_{3}^{4} x + \frac{1}{3} x^{3} d x

\int_{3}^{5} x^{2} + 4 d x

\int_{0}^{c o s (y)} sin (y) d y

\int_{0}^{x^{2}} x^{2} (1 + x) d x

What is the integral from-infinity to 7 of θe^θ ?
The integral from-infinity to 7 of θe^θ is 6e^7