What is the integral from 1 to 2 of 1/x ?

The integral from 1 to 2 of 1/x is ln(2)

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integral from 1 to 2 of 1/x

\int_{1}^{2} \frac{1}{x} d x

ln (2)

Decimal Notation

0.69314 \dots

Solution steps

\int_{1}^{2} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{1}^{2}

Compute the boundaries:

ln (2)

= ln (2)

\frac{\partial}{\partial x} (3 x yz)

n = 1 \sum \infty 2^{n} (n!)^{2}

\int_{1}^{3} (4 x^{3} - 8 x + 1) d x

\frac{d}{d x} (\frac{4}{x} + x^{2})

\int \frac{1}{5 - 3 cos ( x )} d x

What is the integral from 1 to 2 of 1/x ?
The integral from 1 to 2 of 1/x is ln(2)