What is the derivative of 4/x+x^2 ?

The derivative of 4/x+x^2 is -4/(x^2)+2x

What is the first derivative of 4/x+x^2 ?

The first derivative of 4/x+x^2 is -4/(x^2)+2x

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\frac{d}{d x} (\frac{4}{x} + x^{2})

- \frac{4}{x ^{2}} + 2 x

Solution steps

\frac{d}{d x} (\frac{4}{x} + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{4}{x}) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

= - \frac{4}{x ^{2}} + 2 x

\int \frac{1}{5 - 3 cos ( x )} d x

\int 8 e^{4 x} (e^{4 x} - 4)^{\frac{1}{5}} d x

y^{^{'}} + \frac{1}{x} y = 5 x^{2}

2 y^{^{''}} + 26 y = 0, y (0) = 9, y^{^{'}} (0) = 5

\frac{\partial}{\partial x} (9 x^{2} + 25 y^{2} - 225)

What is the derivative of 4/x+x^2 ?
The derivative of 4/x+x^2 is -4/(x^2)+2x
What is the first derivative of 4/x+x^2 ?
The first derivative of 4/x+x^2 is -4/(x^2)+2x